The equilibrium constant, kc for the reaction is 0,04 at temperature T. Calculate the number of moles of iodine present at time t = 6 minutes
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Answer:
At 700 K, the equilibrium constant for the reaction;
H
2(g)
+I
2(g)
⇌2HI
(g)
is 54.8.
If 0.5 mol litre
−1
of HI
(g)
is present at equilibrium at 700 K, what are the concentrations of H
2(g)
and I
2(g)
assuming that we initially started with HI
(g)
and allowed it to reach equilibrium at 700 K.
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