Chemistry, asked by leratobatantse4, 2 days ago

The equilibrium constant, kc for the reaction is 0,04 at temperature T. Calculate the number of moles of iodine present at time t = 6 minutes

Answers

Answered by ashishkumarash75
2

Answer:

At 700 K, the equilibrium constant for the reaction;

H

2(g)

+I

2(g)

⇌2HI

(g)

is 54.8.

If 0.5 mol litre

−1

of HI

(g)

is present at equilibrium at 700 K, what are the concentrations of H

2(g)

and I

2(g)

assuming that we initially started with HI

(g)

and allowed it to reach equilibrium at 700 K.

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