Question

The equilibrium constant (Kp) for the reaction,
2SO2(g) + O2(g) ⇌ 2SO3(g) at 1000 K is 3.5 atm–1
What would be the partial pressure of oxygen gas, if the equilibrium is found to have equal moles of SO2 and SO3?

Answer 1

Answer: P of O2 = 0.2857

Explanation: 2SO2 + O2 -> 2SO3

K= (SO3)2 / (SO2)2 (O2)

Since SO3 and SO2 are equal and will cancel out and Pressure of O2 will be reciprocal of K i.e. 0.2857