The equilibrium constant kp for the reaction pcl5(g) pcl3(g) + cl2(g) is 16 if the volume
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The equilibrium constant \
so Δn=3-1=2
Here the value is positive Then kp is more than kc
if volume of the container is reduced to one half then the value of kp at the same temperature
Hence PCl5 will be consumed and its pressure will decrease
Also, PCl3 & Cl2 will form and their pressure will increase
It will be 16
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