Question

The equilibrium constant kp for the reaction pcl5(g) pcl3(g) + cl2(g) is 16 if the volume

Answer 1

Answer:

The equilibrium constant   \$K_{p} =16$

so Δn=3-1=2

Here the value is positive Then kp is more than kc

$[K_{p} =K_{c} (RT)^{delta n}$

if volume of the container is reduced to one half then the value of kp at the  same temperature

Hence PCl5 will be consumed and its pressure will decrease

Also, PCl3 & Cl2 will form and their pressure will increase

It will be 16