Question

The equilibrium constant KP for the thermal dissociation of PCL5 at 200 degree celsius is 1.6 ATM what is the pressure at which it is 50% dissociated

Answer 1

Explanation:

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Answer 2

Given:

Equilibrium constant, Kp = 1.6

To Find:

Pressure at 50% dissociated = ?

Solution:

$PCL_{5} \rightleftharpoons PCL_{3}+CL_{2}$

Total number of moles at equilibrium will be:

= $\frac{1}{2} +\frac{1}{2} +\frac{1}{2}$

= $\frac{1+1+1}{2}$

= $\frac{3}{2}$

Now,

Equilibrium Constant,

⇒  $Kp=\frac{\frac{1}{2}\times \frac{1}{2}}{\frac{1}{2}}\times \frac{P}{\frac{3}{2}}$

⇒  $1.6=\frac{1}{4} \times 2\times \frac{2P}{3}$

⇒  $1.6=\frac{4}{4}\times \frac{P}{3}$

⇒  $1.6=\frac{P}{3}$

⇒  $P=1.6\times 3$

⇒  $P=4.8 \ atm$

So that the pressure will be "4.8 atm".