Question

The equilibrium constant of acetic acid in an aqueous solution of concentration C is given by.

Answer 1

Answer : K=cΛ2cΛ∞(Λ∞−Λc)

We have

CH3COOH⇋CH3COO−+H+

K=[CH3COO][H+][CH3COOH]=cα2(1−α)

Since α=Λc/Λ∞ we get

K=c(Λc/Λ∞)21−(Λc/Λ∞)

⇒cΛ2cΛ∞(Λ∞−Λc)

Answer 2

HEYA!!

$\begin{array}{1 1}K=\large\frac{c\Lambda_c^2}{\Lambda^{\infty}-\Lambda_c}\\K=\large\frac{c\Lambda_c^2}{\Lambda^{\infty}(\Lambda^{\infty}-\Lambda_c)}\\K=\large\frac{c\Lambda_c^2}{\Lambda^{\infty}+\Lambda_c}\\K=\large\frac{c\Lambda_c^2}{\Lambda^{\infty}(\Lambda^{\infty}+\Lambda_c)}\end{array} $

HOPE IT WORKS!!

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