Chemistry, asked by riwalrana, 10 months ago

The equilibrium constant of mutarotation of -d-glucose to -d-glucose is 1.8. If specific rotation of -d-glucose is 112o and that of mixture is 59o ; what is specific rotation of -d-glucose

Answers

Answered by Rameshjangid
0

The equilibrium constant of mutarotation of -d-glucose to -d-glucose is 1.8 the rotation of the solution slowly increases from the starting value of + 18.7° to the same equilibrium value of + 54° when -d-glucose dissolves in water.

Mutarotation is the name for this progressive shift in rotation toward an equilibrium point.

  • There are two conceivable arrangements for the OH group on the C-1 of sugars. This results in the formation of two stereoisomers, referred to as "anomers": the "-" and the "-" anomers.
  • An intriguing thing happens when you test the optical rotation of pure "" or pure "" in water. Over time, the optical rotation gradually changes!
  • The observed shift in the optical rotation of the - and - anomers of glucose upon solvent dissolution is referred to as "mutarotation" (literally, "change in rotation").
  • The - and - forms gradually interconvert until equilibrium is reached as a result of ring-chain tautomerism.

To know more, click here:

https://brainly.in/question/15422028

https://brainly.in/question/47662800

#SPJ1

Similar questions