Chemistry, asked by amansuri120304, 1 month ago

The equilibrium constant of the given cell reaction at 298 K will be Mg(s) + Cu²+ (aq) → Mg²+ (aq) + Cu(s) 1 (Given: Excell = 2.7V)​

Answers

Answered by theamar3158
0

Answer:

(a) For the cell reaction,

Mg(s)+Cu

2

+(aq)→Mg

2

+(aq)+Cu(s); E

o

cell=+2⋅71V

The change in the standard Gibbs free energy is given as:

ΔrG

o

=−nFE

o

cell=−2×96500×2.71=−523030 Jmol

−1

b) The fuel cell which uses the reaction of hydrogen with oxygen to form water was used in Apollo space programme for providing electrical power.

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