Question

The equilibrium constant of the reaction :
Cu(s)+2Ag+(aq)→Cu2+(aq)+2Ag(s);
Eo=0.46V at 298 K is :

Answer 1

Answer:

Hey there,

We are given that the equilibrium constant of the reaction:

Cu(s) + 2Ag+(aq) ---->Cu2+(aq) + 2Ag(s)

We can get the equilibrium constant for the reaction by

K=[Cu+2][Ag]^2/[Ag+]^2[Cu]

And we have  

[Cu](s) =1 and [Ag](s) =1

So,  the overall equilibrium constant is

K= [Cu+2]/[Ag+]^2

When the chemical is equilibrium constant, we can say that there will be no change of the reactants and the products over time.  

Thanks for asking

Answer 2

the correct answer is
K=[Cu+2]/[Ag+]²