Question

The equilibrium p4 (s) + 6cl2 (g) â 4pcl3(g) is attained by mixing equal number of moles of reactants. Then at equilibrium

Answer 1

The concentration of P₄ will be more than the concentration of Cl₂

• From the reaction P₄ (S) + 6Cl₂ (g) ⇔ 4PCl₃ (g)  it is clear that 1 mole of P₄ reacts with 6 moles of Cl₂
• If both the reactants were taken in equal amounts i.e, 1 mole in a vessel then for attaining equilibrium 6 moles of  Cl₂ gets consumed
• Complete P₄ will not be consumed and some concentration of P₄ will remain at equilibrium

• So the concentration of P₄ is greater thn the concentration of Cl₂ at equillibrium i.e, [P₄] > [Cl₂]