Question

The equimolar mixture of NaOH and KOH wa.
neutralised by x grams of H,SO,. Then x is (Where
n is number of moles each of NaOH and KOH)​

Answer 1

Each mole of NaOh and KOH gives 1 mole of OH- ions, Si, total moles of OH- = 2n

Now, one mole of H2SO4 gives 2 moles of (H+)

So, to neutralise, only 1 mole of H2SO4 is required which weighs 98 g

Hence, X= 98g.

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