Question

the equivalent capacitance between a and b​

Answer 1

⁕ Kindly learn equipotential method for rearranging the circuit.

Let us assume unknown potential be x.

❖ Observe the attachment,

❋ 1 μF is in parallel with 1 μF,

$\sf \implies (1 +1)\ \mu F$

$\sf \implies 2\ \mu F$

◈ Now, this resultant capacitance is in series with 1 μF,

$\sf \implies \dfrac{2 \times 1}{2+1}$

$\implies \sf \dfrac{2}{3}\ \mu F$

◈ Now, this resultant capacitance is in parallel with 2 μF,

$\implies \sf \left(\dfrac{2}{3}+2 \right)\ \mu F$

$\orange{\implies \sf \dfrac{8}{3}\ \mu F\ \; \bigstar}$

Option 2

More Info:

◈ If n capacitors are connected in parallel,

$\implies \rm \orange{C_{parallel}=C_1+C_2+...\ +C_n}$

◈ If n capacitors are connected in series,

$\implies \rm \green{\dfrac{1}{C_{series}}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+...\ +\dfrac{1}{C_n}}$