Physics, asked by krisha1402, 9 months ago

The equivalent capacitance between points A and B is

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Answers

Answered by Anonymous
47

Question :

The effective capacitance between the points P &B.

Theory :

Combination of Capacitors

1) Series combination

In Series combination, each capacitor has equal charge for any value of capacitances .

⇒Capacitors in series :

For n capacitors connected in series the equivalent capacitance

 \dfrac{1}{c_{eq} }  =  \dfrac{1}{c_{1} }  +  \dfrac{1}{c_{2} }  + ..... +  \dfrac{1}{c_{n} }

2) Parallel Combination

When capacitors are connected in parallel,the potential difference across each capacitor is same .

⇒Capacitors in Parallel :

For n capacitors connected in parallel, the equivalent capacitance is given by ;

c_{eq} = c_{1} + c_{2} + ....  c_{n}

Solution :

{\purple{\boxed{\large{\bold{C_{eq}=\dfrac{10}{3}\mu\:F}}}}}

Refer to the attachment

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Answered by abdulrubfaheemi
1

Answer:

Question :

The effective capacitance between the points P &B.

Theory :

Combination of Capacitors

1) Series combination

In Series combination, each capacitor has equal charge for any value of capacitances .

⇒Capacitors in series :

For n capacitors connected in series the equivalent capacitance

\dfrac{1}{c_{eq} } = \dfrac{1}{c_{1} } + \dfrac{1}{c_{2} } + ..... + \dfrac{1}{c_{n} }

c

eq

1

=

c

1

1

+

c

2

1

+.....+

c

n

1

2) Parallel Combination

When capacitors are connected in parallel,the potential difference across each capacitor is same .

⇒Capacitors in Parallel :

For n capacitors connected in parallel, the equivalent capacitance is given by ;

c_{eq} = c_{1} + c_{2} + .... c_{n}c

eq

=c

1

+c

2

+....c

n

Solution :

{\purple{\boxed{\large{\bold{C_{eq}=\dfrac{10}{3}\mu\:F}}}}}

C

eq

=

3

10

μF

Refer to the attachment

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