Question

the equivalent capacitance between the points A and B in given circuit is
1) 1 microcoulomb
2) 2 microcoulomb
3) 3 microcoulomb
4) 4 microcoulomb

Answer 1

The three capacitors whose values are 3 μF, 3 μF and 3 μF are in series.

Hence, we will use the series formula to find the capacitance:

$= \frac{1}{3} +\frac{1}{3} +\frac{1}{3}$

C(net) = 1 μF

Now, 1 μF and C(net) are in parallel, hence we will use parallel formula:

= 1 μF + 1 μF = 2 μF

Now, the other 1 μF and 1 μF are also in parallel:

Hence, 1 μF + 1 μF = 2 μF

Now, the 2 μF and 2 μF are in series:

Hence,

$\frac{1}{C_e_q} =\frac{1}{2}+ \frac{1}{2}$

$C_e_q = 1$ μF

Hence, the option (1) is correct.