Question

The equivalent capacitance of the arrangement given in the above circuit is​

Answer 1

Answer:

Two 1.5 μ F capacitors are in parallel

∴C

p

=1.5+1.5=3μF

Three 3μF capacitors are in series

∣therefore

C

eq

1

=

3

1

+

3

1

+

3

1

=

3

3

=1

∴c

eq

=1μF