The equivalent capacitance of the combination, as shown in the figure, between point A and B is
Answers
Given : A circuit of capacitance
To Find : The equivalent capacitance of the combination between point A and B is
Solution:
The given circuit can be compared to wheat stone bridge
where 10 /20 = 20/40 = 1/2
Hence balanced so capacitor 30 μF can be removed
so 10 and 20 μF are in series
20 and 40 μF are in series
and combination of both are in parallel
capacitor in series 1/C = 1/C₁ + 1/C₂
capacitor in parallel C = C₁ + C₂
10 and 20 μF are in series = 1/(1/10 + 1/20 ) = 20/3 μF
20 and 40 μF are in series = 1/(1/20 + 1/40) = 40/3 μF
20/3 μF and 40/3 μF in parallel
Hence The equivalent capacitance of the combination between point A and B is = 20/3 + 40/3 = 60/3 = 20 μF
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Answer:
4 th option is the correct answer.
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