Math, asked by chamolisanty, 4 months ago

The equivalent capacitance of the input loop of
the circuit shown is:

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Answers

Answered by kiranladdha77
0

Answer:

We know, Q = CV

But voltage across capacitor is constant.

C ∝ Q

⇒ C ∝ i

∴ Ctotal ∝ (i1 + i2)

Cin ∝ li

∴ Cin =

is

(i1 + i2)

Ctotal =

i1

(100 μF)

(i1 + 49i1)

=

i1

(100 μF) = 2μF

50i1

Alternately

Vin = 2RI1 +

1

50

jωC

I1 = 2RI1 +

1

I1

jωCeq

∴ Ceq =

C

= 2 μF

50

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