The equivalent capacitance of the two capacitors having equal capacitance connected in
parallel is 7.50 uF. Their combination is connected to the battery having voltage 16 V.
Calculate the charge stored on each capacitor.
(a) 60 pc
(b) 60 UF
(c) 60 μC
(d) 120 C
Answers
Answered by
4
Given :-
Equivalent Capacitance of two Capacitor in Parallel is = 7.5 μF
Voltage = V = 16 V
Now as per fomula,
Q = CV/2
Here we divide it by (2) to find charge in each case.
Q = (7.5 × 60)/2
Q = 120/2
Q = 60 μC
Hence,
Charge on each Capacitor = Q = 60 μC.
Answered by
0
Answer:
60
Explanation:
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