Question

the equivalent capacity of two capacitor in series is 3 micro farad and in parallel is 16 micro farad. what are their individual capacities​

Answer 1

Given that,

The equivalent capacity of two capacitor in series is 3 μF and in parallel is 16 μ F.

To find,

Their individual capacities​.

Solution,

For series combination, equivalent capacitance is given by :

$\dfrac{1}{C_s}=\dfrac{1}{C_1}+\dfrac{1}{C_2}$

We have, $C_s=3\ \mu F$

So,

$\dfrac{1}{3}=\dfrac{1}{C_1}+\dfrac{1}{C_2}\ ......(1)$

For parallel combination, the equivalent capacitance is given by :

$C_p=C_1+C_2$

We have, $C_p=16\ \mu F$

So,

$16=C_1+C_2\ .....(2)$

We need to solve equation (1) and (2) to find the value of C₁ and C₂. If we solve them, we get :

$C_1=4\ \mu F\\\\C_2=12\ \mu F$

So, their individual capacities are 4 and 12 microfarads.

Answer 2

Hope it helps you

Plz mark me as brainliest