Chemistry, asked by muratbhau90, 5 months ago

The equivalent conductance of 0.10 N solution of MgCl2 is 97.1 ohm 1 cm2 equt" at 25°C, the Specific conductance is
ohm-1cm-1​

Answers

Answered by vs6338203
0

Explanation:

Given Δ

eq

=97.1mhocm

2

equi

−1

Concentration of MgCl

2

=0.10N=C

Surface Area (A) =1.5 cm

2

length (l) = 0.5 cm

Now, Δ

eq

=K×

C

1000

97.1=K×

0.1

1000

K = 0.0097 mho cm

2

Now, R=ρ

A

l

Since ρ=

K

1

=

0.0097

1

=103.093ohm.cm

R=103.093×

1.5

0.5

=34.36ohm

According to ohm's Law

V = IR

V = 5 volt, R = 3.36 ohm

5=I×34.36

I=0.145Ampere

Hence option (D) is correct.

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