The equivalent conductance of 0.10 N solution of MgCl2 is 97.1 ohm 1 cm2 equt" at 25°C, the Specific conductance is
ohm-1cm-1
Answers
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0
Explanation:
Given Δ
eq
=97.1mhocm
2
equi
−1
Concentration of MgCl
2
=0.10N=C
Surface Area (A) =1.5 cm
2
length (l) = 0.5 cm
Now, Δ
eq
=K×
C
1000
97.1=K×
0.1
1000
K = 0.0097 mho cm
2
Now, R=ρ
A
l
Since ρ=
K
1
=
0.0097
1
=103.093ohm.cm
R=103.093×
1.5
0.5
=34.36ohm
According to ohm's Law
V = IR
V = 5 volt, R = 3.36 ohm
5=I×34.36
I=0.145Ampere
Hence option (D) is correct.
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