Question

The equivalent conductance of Al2(SO4)3 at a certain concentration is 40 S cm2 equi–1. Its molar conductance at this concentration is

Answer 1

Answer:

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Answer 2

Answer:

Required molar conductance

$6 \times 40 = 240 \: S cm2 equi–1.$

Explanation:

Given,Al₂(So₄)₃

Let the no of cations $= {n}^{ + }$

Charge of cations $= {z}^{ + }$

then,equivalent conductance,

$\alpha =( \frac{1}{ {n}^{ + } \times {z}^{ + } } ) \times \gamma$

Al₂(So₄)₃ → 2Al + 3So₄

Here Al has 3+ ion and So₄ has 2- ion.

${z}^{ + } = 3 \\ {n}^{ + } = 2$

$\alpha = \frac{1}{2 \times 3} \times \gamma \\ \alpha = \frac{ \gamma }{6}$

So, molar conductance =$6 \times$ equilvalent conductor

i.e,molar conductance=$6 \times 40 = 240 \: S cm2 equi–1.$