Question

The equivalent conductance of ch3cooh at infinite dilution is given by

Answer 1

Answer:

Explanation:

this the explanation of question

Answer 2

Answer:

The equivalent conductance of ch3cooh at infinite dilution is given by Kohlrausch's Law

Explanation:

• It states that the equivalent conductivity of an electrolyte at infinite dilution of the solution is equal to the sum of the equivalent conductance of the anions and cations contained in the solution.
• Acetic acid is a weak acid and is partially dissociated in an aqueous solution.
• The hydrogen ion concentration in the aqueous solution depends on two factors. One is the degree of dissociation of acetic acid and the other is the initial concentration of acetic acid.

$&\Lambda_{\mathrm{CH}_{3} \mathrm{COONa}}^{\infty}=\lambda_{\mathrm{CH}_{3} \mathrm{COO}^{-}}^{\circ}+\lambda_{\mathrm{Na}^{-}}^{\circ}$

$&\Lambda_{\mathrm{HCl}}^{0}=\lambda_{\mathrm{H}^{+}}^{0}+\lambda_{\mathrm{Cr}}^{0}$

$&\Lambda_{\mathrm{NaCl}}^{\infty}=\lambda_{\mathrm{Na}^{+}}^{\infty}+\lambda_{\mathrm{Cl}^{-}}^{0}$

$&\Lambda_{\mathrm{CH}_{3} \mathrm{COOH}}^{\infty}=\Lambda_{\mathrm{CH}_{3} \mathrm{COONa}}^{\infty}+\Lambda_{\mathrm{HCl}}^{\infty}-\Lambda_{\mathrm{NaCl}}^{\infty}$

$&\Rightarrow 91+426+(-126)=391=\Lambda_{\mathrm{CH}_{3} \mathrm{COOH}}^{\infty}$

$&\Lambda_{C}=19.55$

$&\alpha=\frac{\Lambda_{\mathrm{C}}}{\Lambda^{\infty}}=\frac{19.55}{391}=0.05$

$&\left[\mathrm{H}^{+}\right]=\alpha \mathrm{C}=1 \times 0.05 \mathrm{M}\\&\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]=-\log \left(5 \times 10^{-2}\right)$

$&\Rightarrow 2-\log 5=2-0.7=1.3$