Physics, asked by racharla8375, 6 months ago

The equivalent conductance of decinormal solution of acetic acid at 298k is 80 and infinite dilution

Answers

Answered by sinchana0512
2

Answer:

The equivalenet conductivites of acetic acid at

at the concentration of

and

are

and

respectively.

Answered by greeshmakachirayil
0

Answer: The answer will be 1.3% and 12.5 %

Explanation:

Did you mean

The equivalent conductance of decinormal acetic acid at 298k at the concentration of 0.1 M and 0.001 M are 5.20 and 49.2 S cm^{2}eq^{-1} respectively. Calculate the degree of dissociation of acetic acid at these concentrations. Given that  λ^∞ (CH_{3}COOH^{-}) are 349.8 and 40.9 ohm^{-1} cm^{2}mol^{-1} respectively.

As we know degree of dissociation can be calculated by the formula ,

\alpha = λeq/λeq^∞

λ^∞(CH_{3}COOH^{-}) = (40.9+ 349.8) ohm^{-1} cm^{2}mol^{-1}

λ^∞(CH_{3}COOH^{-}) = 390.7 ohm^{-1} cm^{2}mol^{-1}

Lets take the question into two cases,

CASE 1 : 0.1 M concentration

\alpha = λeq/λeq^∞

Putting the values in the given formula

\alpha _{1}= \frac{5.2}{390.7}

\alpha _{1}= 0.013 or 1.3%%

Answer ) The degree of dissociation of acetic acid at 298k and 0.1 M concentration is 1.3 %

CASE 2 : 0.001 M concentration

\alpha = λeq/λeq^∞

Putting the values in the given formula

\alpha =\frac{49.2}{390.7}

\alpha = 0.125 or 12.5%

ANSWER ) The degree of dissociation of acetic acid at 298k and 0.001 M concentration is 12.5%

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