Question

The equivalent conductance of M/36 solution of a weak monobasic acid is 6 mho cm^2 equiv^-1and at infinite dilution is 400mho cm^2 equiv^-1.calculate the dissociation constant of this acid.

Answer 1

The dissociation constant of this acid is K  = 1.25 × 10^−5

Explanation:

α = ΛE / ΛE∘

α = (8.0 ohm−1cm^2 equiv−1) / (400.0 ohm−1 cm^2 equiv−1)

α = 2 × 10^−2

K  = Cα^2 = 1 / 32 × (2 × 10^−2)

K = 1.25 × 10^−5

Thus the dissociation constant of this acid is K  = 1.25 × 10^−5

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