Question

The equivalent mass of a trivalent metal element is 9 g/eq. The molar mass of its anhydrous oxide is?

Answer 1

Answer : The molar mass of anhydrous oxide is 102 g/mole.

Solution : Given,

Equivalent mass = 9 g/eq

Valency of trivalent metal element = 3

Molar mass of oxygen = 16 g/mole

The molecular formula of trivalent metal oxide is, $M_2O_3$

Formula used :

Molar mass of an element = Equivalent mass × Valency

Now put all the given values in this formula, we get

Molar mass of an element = 9 × 3 = 27

Now we have to calculate the molar mass of $M_2O_3$.

Molar mass of $M_2O_3$ = $(2\times 27)+(3\times 16)=102$

Therefore, the molar mass of anhydrous oxide is 102 g/mole.

Answer 2

• The molar mass of anhydrous oxide is 102 g/mole.

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