Math, asked by jane737, 3 months ago

the equivalent resistance between a and b is​

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Answered by vipinkumar212003
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 \color{blue}\underline{we \: start \: from \: the \: last} \\  \color{red}1Ω \: and \: 1Ω \: in \: series :  \\ R_s = 1 + 1 = 2Ω \\ \color{red}R_s \: and \: 2Ω \: in \: parallel :  \\ R_p =  \frac{R_s \times 2}{R_s + 2}  =  \frac{4}{4}  = 1Ω \\ \color{red}R_p \: and \: 1Ω \: in \: series :  \\ R_{s1} = R_p + 1 = 2Ω \\ \color{red}R_{s1} \: and \: 2Ω \: in \: parallel :  \\ R_{eq} =  \frac{R_{s1} \times 2}{R_{s1} + 2}  =  \frac{4}{4}  \\  \\  \boxed{R_eq = 1Ω} \\  \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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