Question

The equivalent resistance between points A and B in the following circuit is ​

Answer 1

Answer:

5 ohm.

Explanation:

Equivalent resistance =  $(10+10)||(10)||(10+10)$

                                    =  $(\frac{20*10}{20+20} )||(20)$

                                    =  $(\frac{20}{3} )||(20)$

                                    =  $\frac{\frac{20}{3}*20 }{\frac{20}{3}+20 }$

                                    =  $5$ ohm.