Question

The equivalent resistance between points A and D of the combination of resistances shown in figure is a)30Ω b)35Ω c)20Ω d)40Ω

Answer 1

Correct option (a) 30 Ω Explanation: Lower resistance on extreme left and upper resistance on extreme right are ineffective. The resistance R2 and R3 are in series combination. Therefore their equivalent resistance. R'= R2 + R3 =10+10 = 20 Ω. Similarly, the resistance R5 and R6 are in series combination. Therefore their equivalent resistance, R"= R5+ R6 = 10+10 = 20 Ω. Now the equivalent resistances R' and R" are in parallel combination. Therefore their equivalent resistance. Read more on Sarthaks.com - https://www.sarthaks.com/228761/what-will-be-the-equivalent-resistance-between-the-two-points-a-and-d

Answer 2

Answer:

35Ω

Explanation:

Lower resistance on extreme left and upper resistance on extreme right are ineffective. The resistance R₂ and R₃ are in series combination. Therefore their equivalent resistance. R'= R₂ + R₃ =10+20 = 30 Ω.

Similarly, the resistance R₅ and R₆ are in series combination. Therefore their equivalent resistance, R"= R₅+ R₆ = 10+20 = 30 Ω.

Now the equivalent resistances R' and R" are in parallel combination. Therefore their equivalent resistance.

R"' = R' + R''/R' × R'' = (30*30/30 + 30)Ω = 15Ω

Thus equivalent resistabce between A and D. R

=R₁ + R'''+ R₄ = 10 +15 +10 =35Ω