The equivalent resistance of circuit across points A and B is equal to —
[A] 22.5 Ω
[B] 25 Ω
[C] 37.5 Ω
[D] 75 Ω
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Answered by
166
The above circuit can be modified as shown in the diagram fig(i).
Resistor between CD are in series.
So, Resistance between CD = 30+20 = 50ohm
Resistor between EF are in series.
So, Resistance between EF = 30+20 = 50ohm
Resistor between GH are in series.
So, Resistance between GH = 30+20 = 50ohm
Now circuit can be modified as fig(ii)
Resistor between CD are in parallel.
So,
1/R = 1/50+1/50+1/25
1/R = 1/50+1/50+2/50
1/R = 4/50
R = 12.5 ohm
Resistor between AB are in series.
So, Resistance between Ab = 10+12.5+15 = 37.5 ohm
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The current through the 40Ω resistor can be found using Ohm's law: i40Ω = vo ... resistors must be equal. .... Req = (35 + 15 + 25)‖(10 + 40) = 75‖50 = 30 Ω ...... (10) = 22.5 ...
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