Physics, asked by aduuuu10, 10 months ago

The equivalent resistance of the network

shown in the figure between points P and Q is

2
/n
Ω . The value of n is ​

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Answers

Answered by Dead3ill
6

Answer:

n = 3

Explanation:

This circuit is in symmetry...........

So after applying mirror symmetry in the arm between P & Q , we will find that 3 resistors of 2Ω will lie parallel between P & Q.

It's given that equivalent resistance (Req) between P & Q is 2/n

So, 1/Req = 1/2 + 1/2 + 1/2

=>1/Req = 3/2

=> n/2 = 3/2

=> n = 3

Answered by bhatirajni136
0

Explanation:

the equivalent resistance of the network shown in the figure between points p and q is

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