The equivalent resistance of the network
shown in the figure between points P and Q is
2
/n
Ω . The value of n is
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Answered by
6
Answer:
n = 3
Explanation:
This circuit is in symmetry...........
So after applying mirror symmetry in the arm between P & Q , we will find that 3 resistors of 2Ω will lie parallel between P & Q.
It's given that equivalent resistance (Req) between P & Q is 2/n
So, 1/Req = 1/2 + 1/2 + 1/2
=>1/Req = 3/2
=> n/2 = 3/2
=> n = 3
Answered by
0
Explanation:
the equivalent resistance of the network shown in the figure between points p and q is
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