Question

the equivalent resistance of three resistors of 4 ohm, 5 ohm, 20 ohm when connected in series

Answer 1

Answer:

$\boxed{\mathfrak{Equivalent \ resistance \ (R_{eq}) = 29 \ \Omega}}$

Explanation:

Equivalent resistance in series connection:

$\boxed{ \bold{R_{eq} = R_1 + R_2 + R_3 + ... + R_n}}$

According to the question:

$\sf R_1$ = 4 $\sf \Omega$

$\sf R_2$ = 5 $\sf \Omega$

$\sf R_3$ = 20 $\sf \Omega$

So,

$\sf \implies R_{eq} = 4 + 5 + 20 \\ \\ \sf \implies R_{eq} = 29 \: \Omega$

Additional information:

Equivalent resistance in parallel combination:

$\frac{1}{R_{eq} } = \frac{1}{R_{1} } + \frac{1}{R_{2} } + \frac{1}{R_{3} } + ... + \frac{1}{R_{n} }$

Answer 2

$\large{\underline{\underline{\sf{Given-}}}}$

$\sf{1) \:There \: is \: Equivalent \: Resistance \: in \: connection}$

$\sf{2) \:There \: are \: 3 \: resistors \: connected \: in \: series}$

• $\sf{R¹ = 4Ω}$

• $\sf{R² = 5Ω}$

• $\sf{R³ = 20Ω}$

$\large{\underline{\underline{\sf{To \: Find-}}}}$

• $\sf{Required \: Resistance}$

$\large{\underline{\underline{\sf{Solution-}}}}$

We know that, Equivalent Resistance in series connection :

$\large{\boxed{\sf{Req = R¹ + R² + R³}}}$

$\sf{Placing \: Values,}$

$\implies \sf{Req = 4 + 5 + 20}$

$\implies \sf{Req = 29}$

$\large{\boxed{\sf{29Ω}}}$

⛬ $\sf{Required \: Resistance \: is \: 29Ω}$