The equivalent weight of a metal is 4.5 and molecular weight of its chloride is 80.if only one metal atom is present in one molecule of chloride the atomic weight if metal is
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Let the Formula of Metal chloride = MClx
Let y be the At wt of metal
y/x = 4.5
y + 35.5 x = 80
4.5 x + 35.5 x = 80
x=2
therefore y = 2 x 4.5 = 9
the metal with at.mass 9 is Be
the compound is BeCl2
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