Question

The equivalent weight of Al(OH)3 is
do it with complete explanation

Answer 1

Given:

Formula of the substance = $Al(OH)_3$

To find:

Equivalent weight of $Al(OH)_3$ = ?

Formula to be used:

$Equivalent weight = \frac{Molar mass}{n-factor}$

Calculation:

Molar mass of $Al(OH)_3$ = 1 (Al) + 3(O) + 3 (H)  

Molar mass of $Al(OH)_3$ = 1 (27) + 3(16) + 3(1)

Molar mass of $Al(OH)_3$ = 27+ 48+3

Molar mass of $Al(OH)_3$ = 78g

The n-factor for given compound is 3.

Thus the equivalent weight of $Al(OH)_3$ is

$Equivalent weight = \frac{Molar mass}{n-factor}$ $= \frac{78}{3} = 26$g

Conclusion:

The equivalent weight of $Al(OH)_3$ is 26g

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Equivalent weight of metal M is 12. Equivalent weight of Y in compound MY2 which has molecular weight 36 is

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Answer 2

Explanation:

Molecular weight of given compound is 78 and basicity is 3. Therefore, equivalent weight is 378=26.