The equivalent weight of Bayer's reagent
Answers
Answered by
1
Answer:
52.66
Explanation:We know that in basic medium KMnO4 (Mn oxidation state=7)converts into MnO2 (Mn oxidation state=4) so change in oxidation is 3.
Equivalent weight = molecular weight÷change in oxidation state
Molecular mass of KMnO4=158
Equivalent weight of KMnO4=158÷3=52.66
Similar questions