Question

the equivalent weight of divalent metal is 31.82 the weight of the single atom is​

Answer 1

Explanation:

63.64/(6.02×10

23

)

Equivalent weight =

Valency

Molecularweight

Thus, molecular weight =31.82×2=63.64

63.64 g of metal contains 6.023×10

23

atoms of it.

∴1 atom weighs

6.02×10

23

63.64

g.