The equivalent weight of divalent metal is 31.82.the weight of a single atom is
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Explanation:
Equivalent weight =
Valency
Molecularweight
Thus, molecular weight =31.82×2=63.64
63.64 g of metal contains 6.023×10
23
atoms of it.
∴1 atom weighs
6.02×10
23
63.64
g.
Hence, option D is correct.
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