The equivalent weight of Fes2
in the following
reaction is FeS2 + 02 → Fe+3 + SO2
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Answer:
FeS2+O2⟶Fe2O3+SO2
Balanced reaction is
4FeS2+11O2⟶2Fe2O3+8SO2
1 mole of FeS2=11/4 moles of O2
Each O− atom takes 2e− for reduction
∴1O2 molecule takes 4e−
∴ Number of e− gained by O2=411×4=11
∴ Number of e− lost by FeS2=11
∴ Equivalent weight of FeS2 in this reaction= 11M
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