Question

The equivalent weight of K2Cr2O7 in acidic medium is

Answer 1

Hey dear,

● Answer -
Equivalent weight of K2Cr2O7 is 49 g/mol.

● Explanation -
K2Cr2O7 in solution gives following ions -
K2Cr2O7 + 14H+ + 6e- → 2K+ + 2Cr3+ + 7H2O

Here, 6 e- participate in the reaction, hence chemical equivalent is 6.

Equivalent weight is calculated by -
Z = W / E
Z = 294 / 6
Z = 49 g/mol

Equivalent weight of K2Cr2O7 in acidic medium is 49 g/mol.

Hope this helps you.
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Answer 2

Answer:

49 g

Explanation:

Potassium dichromate in acidic medium is a strong oxidizer. It means it gains electrons during redox reaction. Potassium dichromate in acidic solution results in :

K2Cr2O7+14H++6e−→2K++2Cr3++7H2O

Equivalent weight ofK2Cr2O7=

294.26/6

= 49 g

This could have been the simplest answer.

Hope it helps :)