Question

The equivalent weight of k2cr2o7 when it acts as oxidising agent in acidic medium

Answer 1

Potassium dichromate in acidic medium is a strong oxidizer. It means it gains electrons during redox reaction. Potassium dichromate in acidic solution results in :

K 2 C r 2 O 7 + 14 H + + 6 e − → 2 K + + 2 C r 3 + + 7 H 2 O

Equivalent weight of K 2 C r 2 O 7 =

294.2 6

= 49


$or$




molecular weight of pottasium dichromate = 294 , X factor in acidic medium = 6

equivalent weight = molecular weight / X factor

= 294 / 6 = 49

Answer 2

142  equivalent weight of k2cr2o7