The equivalent weight of KMnO4 for acid solution is
(a) 79
(b) 52.16
(c) 158
(d) 31.6
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Mn 7+ changes to Mn 2+ in acidic medium and its equivalent weight becomes M/5
Originally equivalent weight of KMnO4 = 158
Hence in acidic medium it will become M/5 = 158/5 = 31.6
Hence, the correct option is "D"
Originally equivalent weight of KMnO4 = 158
Hence in acidic medium it will become M/5 = 158/5 = 31.6
Hence, the correct option is "D"
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