Question

The equivalent weight of KMnO4 (molar mass = M), when it is converted into Mn2+ is

Answer 1

Explanation:

it is given by

=

molecular mass/n factor

n factor =change in oxidation state

=5

so equivalent weight =M/5

Answer 2

The Molar Mass of M is 16.99g.

Explanation:

M=$Equivalent Mass= \frac{Molecular Mass}{n−factor}$

​  Here n−factor= (change in Oxidation.Number of any element )

The oxidation state of M in $KMNO_{4}$ is +7 and in $Mn_{2}$  is +0.

∴n-factor =1

∴$Equivalent mass=\frac{M}{1}$​

=$\frac{118.936}{7}$

$=16.99g$