the equivalent weight of mnso4 is half of it s molecular weight when it is converted into.....
a) MnO2
b)Mn2O3
c)MNO4-
please
explain meaning of this question and then answer
Answers
Answered by
66
change in oxidation no. when mns04 converted into mn02 is 2 .
equivalent weight = molecular weight/change in oxidation no.
equivalent weight = molecular weight/change in oxidation no.
Answered by
126
in MnSO4 oxidation number of Mn = + 2
we know,
equivalent weight = Molecular mass /n-factor
first of all you have to know,
what is n-factor
n - factor is number for a elements which denotes the change in number of oxidation state of that element .
here , said , equivalent weight is half of molecular weight .
e.g equivalent = Molecular weight/2
so, n-factor = 2
it means oxidation number of Mn+2 change with +2
e.g new oxidation number of Mn = +4
now, check which of the following have +4 oxidation number of Mn .
(a ) option O.N of Mn = +4
so, (a ) is answer
we know,
equivalent weight = Molecular mass /n-factor
first of all you have to know,
what is n-factor
n - factor is number for a elements which denotes the change in number of oxidation state of that element .
here , said , equivalent weight is half of molecular weight .
e.g equivalent = Molecular weight/2
so, n-factor = 2
it means oxidation number of Mn+2 change with +2
e.g new oxidation number of Mn = +4
now, check which of the following have +4 oxidation number of Mn .
(a ) option O.N of Mn = +4
so, (a ) is answer
abhi178:
pleasure , have you understand
but why O.N of mn can't be 2
dear equivalent weight = molecular weight /change in oxidation no
n -factor = change in oxidation no /change in reduction no /acidity /basicity
no direct oxidation number okay
so, we can't use O.N of Mn = +2 only
now ,
please oh i got it i forgot that it is an oxidation reaction so n factor will be change in ON
if like mark brnlst dear !!!
ok
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