Physics, asked by heba81, 11 months ago

The equivalent weight of Nah,PO, in the reaction
NaH2PO4 +KOH-NaKHPO4+H2O is
(Given Atomic masses: Na = 23, K = 39, P = 31)
(1) 158
(2) 60
(3) 97
(4) 120

Answers

Answered by parassolanki

1

Answer:

ans is (4) 120 gm

only one hydrogen atom exchanged so its n factor is 1

equivalent weight = Molar mass ÷ n factor

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