The eqution of a stationary wave is y=12cos(πx/5)sin20πt .where x,y are cm and t is in sec .find wavelength and maximum amplitude of wave
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y=12cos(πx/5)sin20πt
General
y=2Acos(2πx/wavelength) sin2πt/T
Therefore, 2πx/wavelength = πx/5
2/wavelength = 1/5
wavelength = 10 m
2A =12
A=6 m
General
y=2Acos(2πx/wavelength) sin2πt/T
Therefore, 2πx/wavelength = πx/5
2/wavelength = 1/5
wavelength = 10 m
2A =12
A=6 m
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