Question

The eqution of a stationary wave is y=12cos(πx/5)sin20πt .where x,y are cm and t is in sec .find wavelength and maximum amplitude of wave

Answer 1

y=12cos(πx/5)sin20πt

General

y=2Acos(2πx/wavelength) sin2πt/T

Therefore, 2πx/wavelength = πx/5
2/wavelength = 1/5
wavelength = 10 m

2A =12
A=6 m