The equvivalent weight of kmno4 in acidic medium is
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In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons. so, eq wt = 158/5 = 31.6 g. Hence, eq wt = 158/3 = 52.67g.
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MARK BRAINLIEST
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52.67 g that s the answer
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