Question

The erect image formed by a concave mirror is of size double the size of object. How are u and v related ?​

Answer 1

$\mathtt {Magnification \: can \: be \: given \: by : } \\ \mathtt {M= -} \mathtt {\frac{v}{u} } \\ \mathtt {Therefore \:,}\mathtt {M= -} \mathtt {\frac{v}{u} = 2} \\ \mathtt {v=-2u} \\ \mathtt {Since ′u′ is \: always \: negative} \\ \:\:\:\:\:\:\: \mathtt {v=2u} \\ \mathtt {The \: above \: equation \: shows} \\ \mathtt { \: how \: u \: and \: v \: are \: related......}$

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Answer 2

Answer:

Magnification can be given by :

m=− v/u

Therefore , − v/u =2

v=−2u

Since u is always negative

v=2u

The above equation shows how u and v are related.