the šeros of
verify that 2and -3
are the zeroes of
polynomial x2+x-6
Answers
Answered by
17
Step-by-step explanation:
Given :
quadratic polynomial x² + x – 6
To verify :
2 and –3 are the zeroes of the given polynomial
Solution :
If 'a' is a zero of the polynomial p(x), then p(a) = 0
Let p(x) = x² + x – 6
To check if 2 is a zero of the given polynomial :
Put x = 2,
p(2) = 2² + 2 – 6
= 4 + 2 – 6
= 6 – 6
= 0
p(2) = 0; hence 2 is a zero of the given polynomial.
To check if –3 is a zero of the given polynomial :
Put x = –3,
p(–3) = (–3)² + (–3) – 6
= 9 – 3 – 6
= 6 – 6
= 0
p(–3) = 0; hence –3 is a zero of the given polynomial.
Hence verified!
Answered by
63
★GIVEN:-
- A Polynomial -- (x^2 + x -6).
★TO VERIFY:-
- Whether 2 and -3 are the roots of the Polynomial.
★SOLUTION:-
First we will put 2 as the root.
Now we will put -3 as the root.
Hence, after putting 2 and -3
The results coming is 0
Therefore, They are the roots of the equation.
HENCE VERIFIED
Similar questions