Question

The error in measurement of radius of a sphere is 0.25% the error in calculation of the volume of the sphere will be

Answer 1

Answer:

hey

mate your answer is....

Explanation:

v=4/3πr^3

v=4/3*3.14*(0.25)^3

v=4/3*3.14*0.01565

v=4/3*0.0490625

v=4*0.0163541667

v=0.065416668cm^2......

......................@rajsingh.........