Science, asked by Suniketshinge, 6 months ago

) The error in measurement of unknown
resistance of X is minimum in a meter
bridge when I = 70 cm, where l is the
distance of null point from one end. If X =
[l/(A-l)]R, find the value of A, where R is
known resistance.
1) 35 cm
3) 140 cm
2) 105 cm
4) 210 cm​

Answers

Answered by vishalbhosale4094
1

Answer:

correct answer is 140cm

Explanation:

Let, X = 1

because X is minimum measurements

given data :-

I = 70cm

R = 1 ( R. is measure's in Ohm)

then put values in given formula

X = [ I / (A -I ) ] × R

therefore

1 = [ 70 / A- 70 ] × 1

then

A = 140 cm

the correct answer is option (B ) 140 cm

Answered by pruthaasl
0

Answer:

The value of A is 3) 140 cm.

Resistance:

  • Resistance is defined as the opposition to the flow of electric current.
  • It is calculated as R=\frac{V}{I}, where R is the resistance, V is the applied voltage, and I is the electric current.
  • Resistance of a wire is directly proportional to its length and inversely proportional to its area of cross-section.

Error Measurement:

  • Defects in the measurement of physical quantities lead to errors. However, these errors can be reduced in different ways.
  • Lesser the error, more is the accuracy in the measurement of a physical quantity.
  • The four types of errors are
  1. Instrumental error
  2. Systematic error
  3. Personal error
  4. Random error

Explanation:

Given: l=70cm

To find: A

Formula: X=\frac{l}{(A-l)} R

Step 1:

The error in unknown resistance X is given to be minimum. Therefore,

\frac{dX}{X} = 0 ...(i)

where dX is the error in X

Step 2:

Using the error measurement formulas, we get

\frac{dX}{X}=[\frac{dl}{l}-\frac{dl}{(A-l)}  ]R , where dl is the error in l

From equation (i)

\frac{dX}{X}=[\frac{dl}{l}-\frac{dl}{(A-l)}  ]R=0

Step 3:

[\frac{dl}{l}-\frac{dl}{(A-l)}  ]R=0

\frac{dl}{l}-\frac{dl}{(A-l)}   = 0

\frac{dl}{l}=\frac{dl}{A-l}

\frac{1}{l}=\frac{1}{A-l}

A-l=l

A=2l

A=2(70)

A=140cm

Therefore, the value of A in the given meter bridge is 140cm.

#SPJ3

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