Physics, asked by anujbhardwaj870849, 9 months ago

the error in the measerment of radius of sphere 2% what woulf br the errorvin the volume of the sphere​

Answers

Answered by Anonymous
36

Given :

▪ Percentage error in measurement of radius of sphere = 2%

To Find :

▪ Percentage error in measurement of volume of sphere.

SoluTion :

↗ Volume of solid sphere :

  • V = 4/3 × πr³

where,

V denotes volume of sphere

r denotes radius of sphere

Percentage error in measurement of volume is given by

%(ΔV/V) = 3 × %(Δr/r)

where,

▪ %(ΔV/V) denotes percentage error in measurement of volume of sphere.

▪ %(Δr/r) denotes peecentage error in measurement of radius of sphere.

Given : %(Δr/r) = 2%

→ %(ΔV/V) = 3 × %(Δr/r)

→ %(ΔV/V) = 3 × (2%)

%(ΔV/V) = 6%


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