the error in the measerment of radius of sphere 2% what woulf br the errorvin the volume of the sphere
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Given :
▪ Percentage error in measurement of radius of sphere = 2%
To Find :
▪ Percentage error in measurement of volume of sphere.
SoluTion :
↗ Volume of solid sphere :
- V = 4/3 × πr³
where,
V denotes volume of sphere
r denotes radius of sphere
❇ Percentage error in measurement of volume is given by
→ %(ΔV/V) = 3 × %(Δr/r)
where,
▪ %(ΔV/V) denotes percentage error in measurement of volume of sphere.
▪ %(Δr/r) denotes peecentage error in measurement of radius of sphere.
Given : %(Δr/r) = 2%
→ %(ΔV/V) = 3 × %(Δr/r)
→ %(ΔV/V) = 3 × (2%)
→ %(ΔV/V) = 6%
BrainIyMSDhoni:
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