Physics, asked by raziakhaleel19874, 3 months ago

The error in the measurement of radius of a shaper is 2%what would be error in (a) volume of sphere (b) surface area of Sphere (c) Total surface area of hemisphere​

Answers

Answered by srishu61
0

Answer:

Given, Error in a radius of the sphere is 2%

it meansΔr=2%

Now, the surface area of the sphere is

A=4πr

2

A

ΔA

=

r

2Δr

A

ΔA

=

1000

2×2

=0.04

A×100

ΔA

=0.04×100= 4%

it means % error in surface area of its measurements is 4%

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