The error in the measurement of radius of a shaper is 2%what would be error in (a) volume of sphere (b) surface area of Sphere (c) Total surface area of hemisphere
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Given, Error in a radius of the sphere is 2%
it meansΔr=2%
Now, the surface area of the sphere is
A=4πr
2
A
ΔA
=
r
2Δr
A
ΔA
=
1000
2×2
=0.04
A×100
ΔA
=0.04×100= 4%
it means % error in surface area of its measurements is 4%
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